2.8x^2-15.2x+15.2=0

Solution for 2.8x^2-15.2x+15.2=0 equation:

2.8x^2-15.2x+15.2=0

a = 2.8; b = -15.2; c = +15.2;
Δ = b2-4ac
Δ = -15.22-4·2.8·15.2
Δ = 60.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.2)-\sqrt{60.8}}{2*2.8}=\frac{15.2-\sqrt{60.8}}{5.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.2)+\sqrt{60.8}}{2*2.8}=\frac{15.2+\sqrt{60.8}}{5.6}
$